(X-9)(x+3)=x^2+4x+13

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Solution for (X-9)(x+3)=x^2+4x+13 equation:



(X-9)(X+3)=X^2+4X+13
We move all terms to the left:
(X-9)(X+3)-(X^2+4X+13)=0
We get rid of parentheses
-X^2+(X-9)(X+3)-4X-13=0
We multiply parentheses ..
-X^2+(+X^2+3X-9X-27)-4X-13=0
We add all the numbers together, and all the variables
-1X^2+(+X^2+3X-9X-27)-4X-13=0
We get rid of parentheses
-1X^2+X^2+3X-9X-4X-27-13=0
We add all the numbers together, and all the variables
-10X-40=0
We move all terms containing X to the left, all other terms to the right
-10X=40
X=40/-10
X=-4

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